As of PHP 5.2, strval() will return the string value of an object, calling its __toString() method to determine what that value is.
strval
(PHP 4, PHP 5)
strval — Bir değişkenin dizgesel değerini döndürür
Açıklama
Bir değişkenin dizgesel değerini döndürür. Dizgeye dönüşümle ilgili daha fazla bilgi için string sayfasına bakınız.
Bu işlev dönen değere hiçbir biçemleme uygulamaz. Sayısal bir değeri bir dizge olarak biçemlemenin bir yolunu arıyorsanız sprintf() veya number_format() işlevi işinizi görebilir.
Değiştirgeler
- değişken
-
Dizgeye dönüşürülecek değişken.
değişken herhangi bir sayıl değer olabilir. strval() işlevini diziler ve nesneler üzerinde kullanamazsınız.
Dönen Değerler
Belirtilen değişken'in string türünde değeri.
Örnekler
Örnek 1 - PHP5'in sihirli __toString yöntemini kullanan strval() örneği
<?php
class StrValTest
{
public function __toString()
{
return __CLASS__;
}
}
// Prints 'StrValTest'
echo strval(new StrValTest);
?>
Ayrıca Bakınız
- floatval() - Bir değişkenin gerçek sayı değerini döndürür
- intval() - Bir değişkenin tamsayı değerini döndürür
- settype() - Bir değişkenin türünü belirler
- sprintf() - Biçemli bir dizge döndürür
- number_format() - Sayıyı binlik bölümlere ayırır
- Tür Dönüşümü
Hayley Watson
21-Aug-2007 02:53
NyctoFixer at gmail dot com
11-Jun-2007 06:19
As of PHP 5.1.4 (I have not tested it in later versions), the strval function does not attempt to invoke the __toString method when it encounters an object. This simple wrapper function will handle this circumstance for you:
<?
/**
* Returns the string value of a variable
*
* This differs from strval in that it invokes __toString if an object is given
* and the object has that method
*/
function stringVal ($value)
{
// We use get_class_methods instead of method_exists to ensure that __toString is a public method
if (is_object($value) && in_array("__toString", get_class_methods($value)))
return strval($value->__toString());
else
return strval($value);
}
?>
kendsnyder+phpnet at gmail dot com
01-Jun-2007 04:08
The only way to convert a large float to a string is to use printf('%0.0f',$float); instead of strval($float); (php 5.1.4).
// strval() will lose digits around pow(2,45);
echo pow(2,50); // 1.1258999068426E+015
echo (string)pow(2,50); // 1.1258999068426E+015
echo strval(pow(2,50)); // 1.1258999068426E+015
// full conversion
printf('%0.0f',pow(2,50)); // 112589906846624
echo sprintf('%0.0f',pow(2,50)); // 112589906846624
portos_ze_retour at hotmail dot fr
10-Mar-2006 01:15
In complement to Tom Nicholson's contribution, here is the french version (actually it's possible to change the language, but you should check the syntax ;) )
function int_to_words($x) {
global $nwords;
if(!is_numeric($x))
$w = '#';
else if(fmod($x, 1) != 0)
$w = '#';
else {
if($x < 0) {
$w = $nwords['minus'].' ';
$x = -$x;
} else
$w = '';
// ... now $x is a non-negative integer.
if($x < 21) // 0 to 20
$w .= $nwords[$x];
else if($x < 100) { // 21 to 99
$w .= $nwords[10 * floor($x/10)];
$r = fmod($x, 10);
if($r > 0)
$w .= '-'. $nwords[$r];
} else if($x < 1000) { // 100 to 999
$w .= $nwords[floor($x/100)] .' '.$nwords['hundred'];
$r = fmod($x, 100);
if($r > 0)
$w .= ' '.$nwords['separator'].' '. int_to_words($r);
} else if($x < 1000000) { // 1000 to 999999
$w .= int_to_words(floor($x/1000)) .' '.$nwords['thousand'];
$r = fmod($x, 1000);
if($r > 0) {
$w .= ' ';
if($r < 100)
$w .= $nwords['separator'].' ';
$w .= int_to_words($r);
}
} else { // millions
$w .= int_to_words(floor($x/1000000)) .' '.$nwords['million'];
$r = fmod($x, 1000000);
if($r > 0) {
$w .= ' ';
if($r < 100)
$word .= $nwords['separator'].' ';
$w .= int_to_words($r);
}
}
}
return $w;
}
// Usage in English
$nwords = array( "zero", "one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen", "seventeen", "eighteen",
"nineteen", "twenty", 30 => "thirty", 40 => "forty",
50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
90 => "ninety" , "hundred" => "hundred", "thousand"=> "thousand", "million"=>"million",
"separator"=>"and", "minus"=>"minus");
echo 'There are currently '. int_to_words(-120223456) . ' members logged on.<br>';
//Utilisation en Francais
$nwords = array( "zéro", "un", "deux", "trois", "quatre", "cinq", "six", "sept",
"huit", "neuf", "dix", "onze", "douze", "treize",
"quatorze", "quinze", "seize", "dix-sept", "dix-huit",
"dix-neuf", "vingt", 30 => "trente", 40 => "quarante",
50 => "cinquante", 60 => "soixante", 70 => "soixante-dix", 80 => "quatre-vingt",
90 => "quatre-vingt-dix" , "hundred" => "cent", "thousand"=> "mille", "million"=>"million",
"separator"=>"", "minus"=>"moins");
echo 'Il y a actuellement '. int_to_words(-120223456) . ' membres connectés.<br>';
anthony dot parsons at manx dot net
09-Jan-2006 02:59
If you have to compare object variables like this be careful not to make a typo, or you could end up calling __set() -
<?php
/* Does what you'd expect it to */
if ( $user->password == $user2->password )
/* Doesn't */
if ( $user->password = $user2->password )
?>
To avoid that ever happening, do it like this:
<?php
if ( strval($user->password) == $user2->password )
?>
php at ianco dot co dot uk
06-Oct-2005 10:36
I can't help being surprised that
(string)"0" == (string)"0.00"
evaluates to true. It's the same with strval and single quotes.
=== avoids it.
Why does it matter? One of my suppliers, unbelievably, uses 0 to mean standard discount and 0.00 to mean no discount in their stock files.
Steve Ball
08-Sep-2005 01:18
It seems that one is being treated as an unsigned large int (32 bit), and the other as a signed large int (which has rolled over/under).
2326201276 - (-1968766020) = 4294967296.
brettsg at serialio dot com
02-Aug-2005 03:07
How come this code in version 4.4 does something different than in version 4.3?
$val = 538759009 ^ 0xAABBCCDD;
print "val=" . $val;
= 2326201276 (version 4.4)
and
= -1968766020 (version 4.3)
Redbeard
24-Aug-2004 08:40
You can also use the PEAR package Numbers_Words, which handles many other languages.
Tom Nicholson
28-Apr-2004 03:13
If you want to convert an integer into an English word string, eg. 29 -> twenty-nine, then here's a function to do it.
Note on use of fmod()
I used the floating point fmod() in preference to the % operator, because % converts the operands to int, corrupting values outside of the range [-2147483648, 2147483647]
I haven't bothered with "billion" because the word means 10e9 or 10e12 depending who you ask.
The function returns '#' if the argument does not represent a whole number.
<?php
$nwords = array( "zero", "one", "two", "three", "four", "five", "six", "seven",
"eight", "nine", "ten", "eleven", "twelve", "thirteen",
"fourteen", "fifteen", "sixteen", "seventeen", "eighteen",
"nineteen", "twenty", 30 => "thirty", 40 => "forty",
50 => "fifty", 60 => "sixty", 70 => "seventy", 80 => "eighty",
90 => "ninety" );
function int_to_words($x) {
global $nwords;
if(!is_numeric($x))
$w = '#';
else if(fmod($x, 1) != 0)
$w = '#';
else {
if($x < 0) {
$w = 'minus ';
$x = -$x;
} else
$w = '';
// ... now $x is a non-negative integer.
if($x < 21) // 0 to 20
$w .= $nwords[$x];
else if($x < 100) { // 21 to 99
$w .= $nwords[10 * floor($x/10)];
$r = fmod($x, 10);
if($r > 0)
$w .= '-'. $nwords[$r];
} else if($x < 1000) { // 100 to 999
$w .= $nwords[floor($x/100)] .' hundred';
$r = fmod($x, 100);
if($r > 0)
$w .= ' and '. int_to_words($r);
} else if($x < 1000000) { // 1000 to 999999
$w .= int_to_words(floor($x/1000)) .' thousand';
$r = fmod($x, 1000);
if($r > 0) {
$w .= ' ';
if($r < 100)
$w .= 'and ';
$w .= int_to_words($r);
}
} else { // millions
$w .= int_to_words(floor($x/1000000)) .' million';
$r = fmod($x, 1000000);
if($r > 0) {
$w .= ' ';
if($r < 100)
$word .= 'and ';
$w .= int_to_words($r);
}
}
}
return $w;
}
?>
Usage:
<?php
echo 'There are currently '. int_to_words($count) . ' members logged on.';
?>
