get_include_path
This function aims to perform filtering of files that have been included :
<?php
function setIncludeFiles($arrayInc = array()){
$incFiles = get_included_files();
if((count($arrayInc)>0)&&(count($incFiles)>0)){
$aInt = array_intersect($arrayInc,$incFiles);
if(count($aInt)>0){
return false;
}elseif(count($aInt)<1) {
foreach($arrayInc as $inc){
if(is_file($inc))
include($inc);
else{
return false;
}
}
}
}else{
return false;
}
}
?>
Usage :
<?php
$toBeInclude = array('/data/your_include_files_1.php',
'/data/your_include_files_2.php',
'/data/your_include_files_3.php',
);
setIncludeFiles($toBeInclude);
?>
Return false if something goes wrong.
get_included_files
(PHP 4, PHP 5)
get_included_files — include나 require한 파일명의 배열을 반환
설명
array get_included_files
( void
)
include(), include_once(), require(), require_once()를 사용하여 포함한 모든 파일명을 얻습니다.
반환값
모든 파일명의 배열을 반환합니다.
호출한 스크립트 파일은 "포함한 파일"로 처리하기에, include() 등으로 참조한 파일과 함께 나옵니다.
여러번 include나 require한 파일은 반환하는 배열에 한번만 나옵니다.
변경점
| 버전 | 설명 |
|---|---|
| 4.0.1 | PHP 4.0.1과 이전 버전에서 이 함수는 .php 확장자로 끝나는 파일만 반환하고, 다른 확장자를 가지는 파일은 반환하지 않았습니다. get_included_files()는 include()와 include_once()로 포함한 파일만 가지는 연관 배열을 반환했습니다. |
예제
Example #1 get_included_files() 예제
<?php
// 이 파일은 abc.php 입니다
include 'test1.php';
include_once 'test2.php';
require 'test3.php';
require_once 'test4.php';
$included_files = get_included_files();
foreach ($included_files as $filename) {
echo "$filename\n";
}
?>
위 예제의 출력:
abc.php test1.php test2.php test3.php test4.php
주의
Note:
auto_prepend_file 설정 지시어를 사용하여 포함한 파일은 반환 배열에 나오지 않습니다.
add a note
User Contributed Notes
get_included_files
donikuntoro at integraasp dot com
28-Aug-2011 09:32
cleggypdc at gmail dot com
23-Jun-2008 03:47
If you want to get the relative path of an included file, from within itself use this function. If you ever have a include file thats path may not be static, this can save some time.
<?php
function get_current_files_path($file_name)
{
//find the current files directory
$includes = get_included_files();
$path = "";
for ($i=0; $i < count($includes); $i++)
{
$path = strstr($includes[$i], $file_name);
if ($path != false)
{
$key = $i;
break;
}
}
$path = str_replace(getcwd(), "", $includes[$key]);
$path = str_replace("\\", "/", $path);
$path = str_replace($file_name, "", $path);
$path = ltrim($path, "/");
return $path;
}
?>
sam at consideropen dot com
29-May-2008 07:57
If you want to avoid the filepaths, just wrap get_included_files() inside preg_replace() to get rid of path info:
<?php
$filenames = preg_replace("/\/.*\//", "", get_included_files());
?>
yarco dot w at gmail dot com
03-Jul-2007 02:27
If you have a MAIN php script which you don't want to be included by other scripts, you could use this function. For example:
main.php:
<?php
function blockit()
{
$buf = get_included_files();
return $buf[0] != __FILE__;
}
blockit() and exit("You can not include a MAIN file as a part of your script.");
print "OK";
?>
So other script couldn't include main.php to modify its internal global vars.
indigohaze at gmail dot com
28-Aug-2006 04:30
Something that's not noted in the docs, if a file is included remotely and you do a get_included_files() in the include itself it will *not* return the document that included it.
ie:
test2.php (server 192.168.1.14):
<?php
include("http://192.168.1.11/test/test3.php");
?>
test3.php (server 192.168.1.11):
<?php
$files = get_included_files();
print_r($files);
?>
returns:
Array ( [0] => /var/www/localhost/htdocs/test/test3.php )
Which means you can use get_included_files() to help intercept and prevent XSS-style attacks against your code.
RPaseur at NationalPres dot org
08-Mar-2006 01:04
As is often the case, YMMV. I tried the __FILE__ and SCRIPT_FILENAME comparison and found this:
SCRIPT_FILENAME: /var/www/cgi-bin/php441
__FILE__: /raid/home/natpresch/natpresch/RAY_included.php
As an alternative:
count(get_included_files());
Gives one when the script is standalone and always more than one when the script is included.
keystorm :at: gmail dotcom
07-Sep-2004 08:08
As of PHP5, this function seems to return an array with the first index being the script all subsequent scripts are included to.
If index.php includes b.php and c.php and calls get_included_files(), the returned array looks as follows:
index.php
a.php
b.php
while in PHP<5 the array would be:
a.php
b.php
If you want to know which is the script that is including current script you can use $_SERVER['SCRIPT_FILENAME'] or any other similar server global.
If you also want to ensure current script is being included and not run independently you should evaluate following expression:
__FILE__ != $_SERVER['SCRIPT_FILENAME']
If this expression returns TRUE, current script is being included or required.