In MySQL 4.1.x, the four TEXT types (TINYTEXT, TEXT, MEDIUMTEXT, and LONGTEXT) return 'blob" as field types, not "string".
mysql_field_type
(PHP 4, PHP 5)
mysql_field_type — 結果において指定したフィールドの型を取得する
説明
string mysql_field_type
( resource
$result
, int $field_offset
)mysql_field_type() は、 mysql_field_name() 関数に似ています。 引数は同じですが、この関数ではフィールドの型が返されます。
パラメータ
-
result -
評価された結果 リソース。 この結果は、mysql_query() のコールにより得られたものです。
-
field_offset -
数値フィールドオフセット。
field_offsetは 0 から始まります。field_offsetが存在しない場合、E_WARNINGレベルのエラーが発行されます。
返り値
返されるフィールド型は "int", "real", "string", "blob", そして その他 » MySQL ドキュメント で詳細が規定されている型のうちのひとつになります。
例
例1 mysql_field_type() の例
<?php
mysql_connect("localhost", "mysql_username", "mysql_password");
mysql_select_db("mysql");
$result = mysql_query("SELECT * FROM func");
$fields = mysql_num_fields($result);
$rows = mysql_num_rows($result);
$table = mysql_field_table($result, 0);
echo "Your '" . $table . "' table has " . $fields . " fields and " . $rows . " record(s)\n";
echo "The table has the following fields:\n";
for ($i=0; $i < $fields; $i++) {
$type = mysql_field_type($result, $i);
$name = mysql_field_name($result, $i);
$len = mysql_field_len($result, $i);
$flags = mysql_field_flags($result, $i);
echo $type . " " . $name . " " . $len . " " . $flags . "\n";
}
mysql_free_result($result);
mysql_close();
?>
上の例の出力は、 たとえば以下のようになります。
Your 'func' table has 4 fields and 1 record(s) The table has the following fields: string name 64 not_null primary_key binary int ret 1 not_null string dl 128 not_null string type 9 not_null enum
注意
注意:
下位互換のために、次の非推奨別名を使用してもいいでしょう。 mysql_fieldtype()
fred at dinkler dot com
08-Feb-2007 04:52
c dot futterlieb at bluewin dot ch
09-Dec-2006 11:06
Additional to the note below:
If you're using the "SHOW FIELDS" syntax, be sure that you're adding the table name instead of the db name in the "FROM" parameter:
<?php
$result = mysql_query("SHOW FIELDS FROM table");
?>
Also possible:
<?php
$result = mysql_query("SHOW FIELDS FROM table.db");
?>
or this:
<?php
$result = mysql_query("DESCRIBE table");
?>
http://dev.mysql.com/doc/refman/5.1/en/describe.html
fusionstream at gmail dot com
17-Sep-2006 03:19
krang at krang dot org dot uk
Condensed version of what KRANG said.
To get info on the MYSQL field type, use this code
<?
$result = mysql_query("SHOW FIELDS FROM db_name");
$i = 1;
while ($row = mysql_fetch_array($result)) { //go through one field at a time
echo "Field $i: ";
print_r($row) //display all information about A field which can be accessed thru the "$row" array.
$i++;
}
?>
Will display something like:
Field 1: Array ( [Field] => SN [Type] => mediumint(8) unsigned [Null] => [Key] => PRI [Default] => [Extra] => auto_increment ) , SN, mediumint(8) unsigned
Field 2: Array ( [Field] => ENTITY_ID [Type] => varchar(20) [Null] => [Key] => [Default] => [Extra] => ) , ENTITY_ID, varchar(20)
18-Feb-2006 04:52
This function is broken in 4.4.1 (works fine in 4.3.X).
http://bugs.php.net/35536
harald at weinreichs dot de
06-Jun-2005 04:02
The note blow seems incomplete/incorrect. For php 4.3 and mysql 4.x the returned values are:
CHAR, VARCHAR, TINYTEXT, TEXT, MEDIUMTEXT, LONGTEXT, ENUM, SET: string
TINYINT, SMALLINT, MEDIUMINT, INT, INTEGER, BIGINT: int
FLOAT, DOUBLE, DECIMAL, NUMERIC: real
TIMESTAMP: timestamp
YEAR: year
DATE: date
TIME: time
DATETIME: datetime
TINYBLOB, MEDIUMBLOB, LONGBLOB, BLOB: blob
if mysql-field-type seems to return the wrong values, you may encounter an compatibility problem of mysql, php and the libraries you use. Try reinstalling php and mysql.
mariob at menta dot net
07-Nov-2003 05:21
For version 4.3.4, types returned are:
STRING, VAR_STRING: string
TINY, SHORT, LONG, LONGLONG, INT24: int
FLOAT, DOUBLE, DECIMAL: real
TIMESTAMP: timestamp
YEAR: year
DATE: date
TIME: time
DATETIME: datetime
TINY_BLOB, MEDIUM_BLOB, LONG_BLOB, BLOB: blob
NULL: null
Any other: unknown
swalif_mesa at hotmail dot com
09-Jul-2003 04:38
Hmm for the previous comment, note that SHOW FIELDS is an alias of SHOW COLUMNS. Very useful if you need to search the mysql-documentation. Here is the link anyway...
http://www.mysql.com/doc/en/SHOW_DATABASE_INFO.html
krang at krang dot org dot uk
09-Mar-2002 11:13
The field type returns what PHP classifies the data found in the field, not how it is stored in the database; use the following example to retrieve the MySQL information about the field....
$USERNAME = '';
$PASSWORD = '';
$DATABASE = '';
$TABLE_NAME = '';
mysql_connect('localhost', $USERNAME, $PASSWORD)
or die ("Could not connect");
$result = mysql_query("SHOW FIELDS FROM $DATABASE.$TABLE_NAME");
$i = 0;
while ($row = mysql_fetch_array($result)) {
echo $row['Field'] . ' ' . $row['Type'];
}
