zip_open
If you get an error like this:
Warning: zip_read() expects parameter 1 to be resource, integer given in xxxxxx on line x
It's because zip_open() failed to open the file and returned an error code instead of a resource. It took me a while to figure out why it failed to open the file, until I tried to use the FULL path to the file.
<?php
// Even if the file exists, zip_open() will return an error code.
$file = 'file.zip';
$zip = zip_open($file);
// The workaround:
$file = getcwd() . '/file.zip';
// Or:
$file = 'C:\\path\\to\\file.zip';
?>
This worked for me on Windows at least. I'm not sure about other platforms.
zip_read
(PHP 4 >= 4.0.7, PHP 5 >= 5.2.0, PECL zip:1.0-1.9.0)
zip_read — Read next entry in a ZIP file archive
Return Values
Returns a directory entry resource for later use with the zip_entry_... functions or FALSE if there's no more entries to read or number of error in case of other error.
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User Contributed Noteszip_read
nico at nicoswd dot com
29-Sep-2007 02:29
29-Sep-2007 02:29